在PHP中创建嵌套的JSON对象如何实现？

摘要： JSON结构可以使用以下代码创建−$json=json_encode(array("client"=>array("build"=>"1.0","name"=>"xxxx","version"=>"1.0"),"protocolVersion"=>4,"data"...

$json = json_encode(array(
   "client" => array(
      "build" => "1.0",
      "name" => "xxxx",
      "version" => "1.0"
   ),
   "protocolVersion" => 4,
   "data" => array(
      "distributorId" => "xxxx",
      "distributorPin" => "xxxx",
      "locale" => "en-US"
   )
));